Optimal. Leaf size=517 \[ -\frac {3 b^2 c \text {Li}_2\left (1-\frac {2}{c x+1}\right ) \left (a+b \tanh ^{-1}(c x)\right )}{c^2 d^2-e^2}+\frac {3 b^2 c \left (a+b \tanh ^{-1}(c x)\right ) \text {Li}_2\left (1-\frac {2 c (d+e x)}{(c d+e) (c x+1)}\right )}{c^2 d^2-e^2}+\frac {3 b^2 c \text {Li}_2\left (1-\frac {2}{1-c x}\right ) \left (a+b \tanh ^{-1}(c x)\right )}{2 e (c d+e)}+\frac {3 b^2 c \text {Li}_2\left (1-\frac {2}{c x+1}\right ) \left (a+b \tanh ^{-1}(c x)\right )}{2 e (c d-e)}+\frac {3 b c \log \left (\frac {2}{c x+1}\right ) \left (a+b \tanh ^{-1}(c x)\right )^2}{c^2 d^2-e^2}-\frac {3 b c \left (a+b \tanh ^{-1}(c x)\right )^2 \log \left (\frac {2 c (d+e x)}{(c x+1) (c d+e)}\right )}{c^2 d^2-e^2}-\frac {\left (a+b \tanh ^{-1}(c x)\right )^3}{e (d+e x)}+\frac {3 b c \log \left (\frac {2}{1-c x}\right ) \left (a+b \tanh ^{-1}(c x)\right )^2}{2 e (c d+e)}-\frac {3 b c \log \left (\frac {2}{c x+1}\right ) \left (a+b \tanh ^{-1}(c x)\right )^2}{2 e (c d-e)}-\frac {3 b^3 c \text {Li}_3\left (1-\frac {2}{c x+1}\right )}{2 \left (c^2 d^2-e^2\right )}+\frac {3 b^3 c \text {Li}_3\left (1-\frac {2 c (d+e x)}{(c d+e) (c x+1)}\right )}{2 \left (c^2 d^2-e^2\right )}-\frac {3 b^3 c \text {Li}_3\left (1-\frac {2}{1-c x}\right )}{4 e (c d+e)}+\frac {3 b^3 c \text {Li}_3\left (1-\frac {2}{c x+1}\right )}{4 e (c d-e)} \]
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Rubi [A] time = 0.52, antiderivative size = 517, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 7, integrand size = 18, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.389, Rules used = {5928, 5918, 5948, 6058, 6610, 6056, 5922} \[ -\frac {3 b^2 c \text {PolyLog}\left (2,1-\frac {2}{c x+1}\right ) \left (a+b \tanh ^{-1}(c x)\right )}{c^2 d^2-e^2}+\frac {3 b^2 c \left (a+b \tanh ^{-1}(c x)\right ) \text {PolyLog}\left (2,1-\frac {2 c (d+e x)}{(c x+1) (c d+e)}\right )}{c^2 d^2-e^2}+\frac {3 b^2 c \text {PolyLog}\left (2,1-\frac {2}{1-c x}\right ) \left (a+b \tanh ^{-1}(c x)\right )}{2 e (c d+e)}+\frac {3 b^2 c \text {PolyLog}\left (2,1-\frac {2}{c x+1}\right ) \left (a+b \tanh ^{-1}(c x)\right )}{2 e (c d-e)}-\frac {3 b^3 c \text {PolyLog}\left (3,1-\frac {2}{c x+1}\right )}{2 \left (c^2 d^2-e^2\right )}+\frac {3 b^3 c \text {PolyLog}\left (3,1-\frac {2 c (d+e x)}{(c x+1) (c d+e)}\right )}{2 \left (c^2 d^2-e^2\right )}-\frac {3 b^3 c \text {PolyLog}\left (3,1-\frac {2}{1-c x}\right )}{4 e (c d+e)}+\frac {3 b^3 c \text {PolyLog}\left (3,1-\frac {2}{c x+1}\right )}{4 e (c d-e)}+\frac {3 b c \log \left (\frac {2}{c x+1}\right ) \left (a+b \tanh ^{-1}(c x)\right )^2}{c^2 d^2-e^2}-\frac {3 b c \left (a+b \tanh ^{-1}(c x)\right )^2 \log \left (\frac {2 c (d+e x)}{(c x+1) (c d+e)}\right )}{c^2 d^2-e^2}-\frac {\left (a+b \tanh ^{-1}(c x)\right )^3}{e (d+e x)}+\frac {3 b c \log \left (\frac {2}{1-c x}\right ) \left (a+b \tanh ^{-1}(c x)\right )^2}{2 e (c d+e)}-\frac {3 b c \log \left (\frac {2}{c x+1}\right ) \left (a+b \tanh ^{-1}(c x)\right )^2}{2 e (c d-e)} \]
Antiderivative was successfully verified.
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Rule 5918
Rule 5922
Rule 5928
Rule 5948
Rule 6056
Rule 6058
Rule 6610
Rubi steps
\begin {align*} \int \frac {\left (a+b \tanh ^{-1}(c x)\right )^3}{(d+e x)^2} \, dx &=-\frac {\left (a+b \tanh ^{-1}(c x)\right )^3}{e (d+e x)}+\frac {(3 b c) \int \left (-\frac {c \left (a+b \tanh ^{-1}(c x)\right )^2}{2 (c d+e) (-1+c x)}+\frac {c \left (a+b \tanh ^{-1}(c x)\right )^2}{2 (c d-e) (1+c x)}+\frac {e^2 \left (a+b \tanh ^{-1}(c x)\right )^2}{(-c d+e) (c d+e) (d+e x)}\right ) \, dx}{e}\\ &=-\frac {\left (a+b \tanh ^{-1}(c x)\right )^3}{e (d+e x)}+\frac {\left (3 b c^2\right ) \int \frac {\left (a+b \tanh ^{-1}(c x)\right )^2}{1+c x} \, dx}{2 (c d-e) e}-\frac {\left (3 b c^2\right ) \int \frac {\left (a+b \tanh ^{-1}(c x)\right )^2}{-1+c x} \, dx}{2 e (c d+e)}+\frac {(3 b c e) \int \frac {\left (a+b \tanh ^{-1}(c x)\right )^2}{d+e x} \, dx}{(-c d+e) (c d+e)}\\ &=-\frac {\left (a+b \tanh ^{-1}(c x)\right )^3}{e (d+e x)}+\frac {3 b c \left (a+b \tanh ^{-1}(c x)\right )^2 \log \left (\frac {2}{1-c x}\right )}{2 e (c d+e)}-\frac {3 b c \left (a+b \tanh ^{-1}(c x)\right )^2 \log \left (\frac {2}{1+c x}\right )}{2 (c d-e) e}+\frac {3 b c \left (a+b \tanh ^{-1}(c x)\right )^2 \log \left (\frac {2}{1+c x}\right )}{(c d-e) (c d+e)}-\frac {3 b c \left (a+b \tanh ^{-1}(c x)\right )^2 \log \left (\frac {2 c (d+e x)}{(c d+e) (1+c x)}\right )}{(c d-e) (c d+e)}-\frac {3 b^2 c \left (a+b \tanh ^{-1}(c x)\right ) \text {Li}_2\left (1-\frac {2}{1+c x}\right )}{(c d-e) (c d+e)}+\frac {3 b^2 c \left (a+b \tanh ^{-1}(c x)\right ) \text {Li}_2\left (1-\frac {2 c (d+e x)}{(c d+e) (1+c x)}\right )}{(c d-e) (c d+e)}-\frac {3 b^3 c \text {Li}_3\left (1-\frac {2}{1+c x}\right )}{2 (c d-e) (c d+e)}+\frac {3 b^3 c \text {Li}_3\left (1-\frac {2 c (d+e x)}{(c d+e) (1+c x)}\right )}{2 (c d-e) (c d+e)}+\frac {\left (3 b^2 c^2\right ) \int \frac {\left (a+b \tanh ^{-1}(c x)\right ) \log \left (\frac {2}{1+c x}\right )}{1-c^2 x^2} \, dx}{(c d-e) e}-\frac {\left (3 b^2 c^2\right ) \int \frac {\left (a+b \tanh ^{-1}(c x)\right ) \log \left (\frac {2}{1-c x}\right )}{1-c^2 x^2} \, dx}{e (c d+e)}\\ &=-\frac {\left (a+b \tanh ^{-1}(c x)\right )^3}{e (d+e x)}+\frac {3 b c \left (a+b \tanh ^{-1}(c x)\right )^2 \log \left (\frac {2}{1-c x}\right )}{2 e (c d+e)}-\frac {3 b c \left (a+b \tanh ^{-1}(c x)\right )^2 \log \left (\frac {2}{1+c x}\right )}{2 (c d-e) e}+\frac {3 b c \left (a+b \tanh ^{-1}(c x)\right )^2 \log \left (\frac {2}{1+c x}\right )}{(c d-e) (c d+e)}-\frac {3 b c \left (a+b \tanh ^{-1}(c x)\right )^2 \log \left (\frac {2 c (d+e x)}{(c d+e) (1+c x)}\right )}{(c d-e) (c d+e)}+\frac {3 b^2 c \left (a+b \tanh ^{-1}(c x)\right ) \text {Li}_2\left (1-\frac {2}{1-c x}\right )}{2 e (c d+e)}+\frac {3 b^2 c \left (a+b \tanh ^{-1}(c x)\right ) \text {Li}_2\left (1-\frac {2}{1+c x}\right )}{2 (c d-e) e}-\frac {3 b^2 c \left (a+b \tanh ^{-1}(c x)\right ) \text {Li}_2\left (1-\frac {2}{1+c x}\right )}{(c d-e) (c d+e)}+\frac {3 b^2 c \left (a+b \tanh ^{-1}(c x)\right ) \text {Li}_2\left (1-\frac {2 c (d+e x)}{(c d+e) (1+c x)}\right )}{(c d-e) (c d+e)}-\frac {3 b^3 c \text {Li}_3\left (1-\frac {2}{1+c x}\right )}{2 (c d-e) (c d+e)}+\frac {3 b^3 c \text {Li}_3\left (1-\frac {2 c (d+e x)}{(c d+e) (1+c x)}\right )}{2 (c d-e) (c d+e)}-\frac {\left (3 b^3 c^2\right ) \int \frac {\text {Li}_2\left (1-\frac {2}{1+c x}\right )}{1-c^2 x^2} \, dx}{2 (c d-e) e}-\frac {\left (3 b^3 c^2\right ) \int \frac {\text {Li}_2\left (1-\frac {2}{1-c x}\right )}{1-c^2 x^2} \, dx}{2 e (c d+e)}\\ &=-\frac {\left (a+b \tanh ^{-1}(c x)\right )^3}{e (d+e x)}+\frac {3 b c \left (a+b \tanh ^{-1}(c x)\right )^2 \log \left (\frac {2}{1-c x}\right )}{2 e (c d+e)}-\frac {3 b c \left (a+b \tanh ^{-1}(c x)\right )^2 \log \left (\frac {2}{1+c x}\right )}{2 (c d-e) e}+\frac {3 b c \left (a+b \tanh ^{-1}(c x)\right )^2 \log \left (\frac {2}{1+c x}\right )}{(c d-e) (c d+e)}-\frac {3 b c \left (a+b \tanh ^{-1}(c x)\right )^2 \log \left (\frac {2 c (d+e x)}{(c d+e) (1+c x)}\right )}{(c d-e) (c d+e)}+\frac {3 b^2 c \left (a+b \tanh ^{-1}(c x)\right ) \text {Li}_2\left (1-\frac {2}{1-c x}\right )}{2 e (c d+e)}+\frac {3 b^2 c \left (a+b \tanh ^{-1}(c x)\right ) \text {Li}_2\left (1-\frac {2}{1+c x}\right )}{2 (c d-e) e}-\frac {3 b^2 c \left (a+b \tanh ^{-1}(c x)\right ) \text {Li}_2\left (1-\frac {2}{1+c x}\right )}{(c d-e) (c d+e)}+\frac {3 b^2 c \left (a+b \tanh ^{-1}(c x)\right ) \text {Li}_2\left (1-\frac {2 c (d+e x)}{(c d+e) (1+c x)}\right )}{(c d-e) (c d+e)}-\frac {3 b^3 c \text {Li}_3\left (1-\frac {2}{1-c x}\right )}{4 e (c d+e)}+\frac {3 b^3 c \text {Li}_3\left (1-\frac {2}{1+c x}\right )}{4 (c d-e) e}-\frac {3 b^3 c \text {Li}_3\left (1-\frac {2}{1+c x}\right )}{2 (c d-e) (c d+e)}+\frac {3 b^3 c \text {Li}_3\left (1-\frac {2 c (d+e x)}{(c d+e) (1+c x)}\right )}{2 (c d-e) (c d+e)}\\ \end {align*}
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Mathematica [C] time = 13.85, size = 813, normalized size = 1.57 \[ -\frac {a^3}{e (d+e x)}-\frac {3 b \tanh ^{-1}(c x) a^2}{e (d+e x)}-\frac {3 b c \log (1-c x) a^2}{2 e (c d+e)}+\frac {3 b c \log (c x+1) a^2}{2 c d e-2 e^2}-\frac {3 b c \log (d+e x) a^2}{c^2 d^2-e^2}+\frac {3 b^2 \left (-\frac {e^{-\tanh ^{-1}\left (\frac {c d}{e}\right )} \tanh ^{-1}(c x)^2}{\sqrt {1-\frac {c^2 d^2}{e^2}} e}+\frac {x \tanh ^{-1}(c x)^2}{d+e x}+\frac {c d \left (i \pi \log \left (1+e^{2 \tanh ^{-1}(c x)}\right )-2 \tanh ^{-1}(c x) \log \left (1-e^{-2 \left (\tanh ^{-1}\left (\frac {c d}{e}\right )+\tanh ^{-1}(c x)\right )}\right )-i \pi \left (\tanh ^{-1}(c x)-\frac {1}{2} \log \left (1-c^2 x^2\right )\right )-2 \tanh ^{-1}\left (\frac {c d}{e}\right ) \left (\tanh ^{-1}(c x)+\log \left (1-e^{-2 \left (\tanh ^{-1}\left (\frac {c d}{e}\right )+\tanh ^{-1}(c x)\right )}\right )-\log \left (i \sinh \left (\tanh ^{-1}\left (\frac {c d}{e}\right )+\tanh ^{-1}(c x)\right )\right )\right )+\text {Li}_2\left (e^{-2 \left (\tanh ^{-1}\left (\frac {c d}{e}\right )+\tanh ^{-1}(c x)\right )}\right )\right )}{c^2 d^2-e^2}\right ) a}{d}+\frac {b^3 \left (\frac {x \tanh ^{-1}(c x)^3}{d+e x}+\frac {3 \left (2 \sqrt {1-\frac {c^2 d^2}{e^2}} e e^{-\tanh ^{-1}\left (\frac {c d}{e}\right )} \tanh ^{-1}(c x)^3+3 c d \tanh ^{-1}(c x)^3-e \tanh ^{-1}(c x)^3-3 c d \log \left (1-e^{\tanh ^{-1}\left (\frac {c d}{e}\right )+\tanh ^{-1}(c x)}\right ) \tanh ^{-1}(c x)^2-3 c d \log \left (1+e^{\tanh ^{-1}\left (\frac {c d}{e}\right )+\tanh ^{-1}(c x)}\right ) \tanh ^{-1}(c x)^2-3 c d \log \left (\frac {1}{2} e^{-\tanh ^{-1}(c x)} \left (e \left (-1+e^{2 \tanh ^{-1}(c x)}\right )+c d \left (1+e^{2 \tanh ^{-1}(c x)}\right )\right )\right ) \tanh ^{-1}(c x)^2+3 c d \log \left (\frac {c (d+e x)}{\sqrt {1-c^2 x^2}}\right ) \tanh ^{-1}(c x)^2+3 i c d \pi \log \left (\frac {1}{2} \left (e^{-\tanh ^{-1}(c x)}+e^{\tanh ^{-1}(c x)}\right )\right ) \tanh ^{-1}(c x)-6 c d \tanh ^{-1}\left (\frac {c d}{e}\right ) \log \left (\frac {1}{2} i e^{-\tanh ^{-1}\left (\frac {c d}{e}\right )-\tanh ^{-1}(c x)} \left (-1+e^{2 \left (\tanh ^{-1}\left (\frac {c d}{e}\right )+\tanh ^{-1}(c x)\right )}\right )\right ) \tanh ^{-1}(c x)+\frac {3}{2} i c d \pi \log \left (1-c^2 x^2\right ) \tanh ^{-1}(c x)+6 c d \tanh ^{-1}\left (\frac {c d}{e}\right ) \log \left (i \sinh \left (\tanh ^{-1}\left (\frac {c d}{e}\right )+\tanh ^{-1}(c x)\right )\right ) \tanh ^{-1}(c x)-6 c d \text {Li}_2\left (-e^{\tanh ^{-1}\left (\frac {c d}{e}\right )+\tanh ^{-1}(c x)}\right ) \tanh ^{-1}(c x)-6 c d \text {Li}_2\left (e^{\tanh ^{-1}\left (\frac {c d}{e}\right )+\tanh ^{-1}(c x)}\right ) \tanh ^{-1}(c x)+6 c d \text {Li}_3\left (-e^{\tanh ^{-1}\left (\frac {c d}{e}\right )+\tanh ^{-1}(c x)}\right )+6 c d \text {Li}_3\left (e^{\tanh ^{-1}\left (\frac {c d}{e}\right )+\tanh ^{-1}(c x)}\right )\right )}{3 c^2 d^2-3 e^2}\right )}{d} \]
Warning: Unable to verify antiderivative.
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fricas [F] time = 0.60, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {b^{3} \operatorname {artanh}\left (c x\right )^{3} + 3 \, a b^{2} \operatorname {artanh}\left (c x\right )^{2} + 3 \, a^{2} b \operatorname {artanh}\left (c x\right ) + a^{3}}{e^{2} x^{2} + 2 \, d e x + d^{2}}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (b \operatorname {artanh}\left (c x\right ) + a\right )}^{3}}{{\left (e x + d\right )}^{2}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [C] time = 0.89, size = 3497, normalized size = 6.76 \[ \text {output too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \frac {3}{2} \, {\left (c {\left (\frac {\log \left (c x + 1\right )}{c d e - e^{2}} - \frac {\log \left (c x - 1\right )}{c d e + e^{2}} - \frac {2 \, \log \left (e x + d\right )}{c^{2} d^{2} - e^{2}}\right )} - \frac {2 \, \operatorname {artanh}\left (c x\right )}{e^{2} x + d e}\right )} a^{2} b - \frac {a^{3}}{e^{2} x + d e} - \frac {{\left ({\left (c^{2} d e - c e^{2}\right )} b^{3} x - {\left (c d e - e^{2}\right )} b^{3}\right )} \log \left (-c x + 1\right )^{3} + 3 \, {\left (2 \, {\left (c^{2} d^{2} - e^{2}\right )} a b^{2} - {\left ({\left (c^{2} d e + c e^{2}\right )} b^{3} x + {\left (c d e + e^{2}\right )} b^{3}\right )} \log \left (c x + 1\right )\right )} \log \left (-c x + 1\right )^{2}}{8 \, {\left (c^{2} d^{3} e - d e^{3} + {\left (c^{2} d^{2} e^{2} - e^{4}\right )} x\right )}} - \int \frac {{\left ({\left (c^{2} d e - c e^{2}\right )} b^{3} x - {\left (c d e - e^{2}\right )} b^{3}\right )} \log \left (c x + 1\right )^{3} + 6 \, {\left ({\left (c^{2} d e - c e^{2}\right )} a b^{2} x - {\left (c d e - e^{2}\right )} a b^{2}\right )} \log \left (c x + 1\right )^{2} + 3 \, {\left (4 \, {\left (c^{2} d e - c e^{2}\right )} a b^{2} x + 4 \, {\left (c^{2} d^{2} - c d e\right )} a b^{2} - {\left ({\left (c^{2} d e - c e^{2}\right )} b^{3} x - {\left (c d e - e^{2}\right )} b^{3}\right )} \log \left (c x + 1\right )^{2} - 2 \, {\left (b^{3} c^{2} e^{2} x^{2} + b^{3} c d e - 2 \, {\left (c d e - e^{2}\right )} a b^{2} + {\left (2 \, {\left (c^{2} d e - c e^{2}\right )} a b^{2} + {\left (c^{2} d e + c e^{2}\right )} b^{3}\right )} x\right )} \log \left (c x + 1\right )\right )} \log \left (-c x + 1\right )}{8 \, {\left (c d^{3} e - d^{2} e^{2} - {\left (c^{2} d e^{3} - c e^{4}\right )} x^{3} - {\left (2 \, c^{2} d^{2} e^{2} - 3 \, c d e^{3} + e^{4}\right )} x^{2} - {\left (c^{2} d^{3} e - 3 \, c d^{2} e^{2} + 2 \, d e^{3}\right )} x\right )}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {{\left (a+b\,\mathrm {atanh}\left (c\,x\right )\right )}^3}{{\left (d+e\,x\right )}^2} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\left (a + b \operatorname {atanh}{\left (c x \right )}\right )^{3}}{\left (d + e x\right )^{2}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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